Calculating the Mass of a Binary Star System

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In a binary star system with one star mass m1=6*1.99*10^30kg and an orbital period of T=1.7 days, the goal is to calculate the mass of the second star, m2, and determine its type. The gravitational force equations are used to relate the masses and radii of the stars, with the orbital period being the same for both. The discussion highlights the need to derive the radius r2 of the second star to find m2, using the equation G*m1m2/(r1+r2)^2=m1(2pi/T)^2*r1. Participants suggest using multiple equations to solve for the unknowns, emphasizing the interconnectedness of the variables in binary systems. The conversation underscores the complexity of calculating masses in such systems while considering gravitational interactions.
coltsamuel96
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mass of a star...

given is a binary star system, with mass m1=6*1.99*10^30kg, radius =r1, v=270km/s, orbital period, T=1.7days... the other star of the binary system(compact and dense)with mass m2, and radius r2 orbits around a same common point... (r1>r2, G=6.67*10^-11Nm^2kg^-2) calculate, 1.)approximate mass of m2 2.)what type of star is m2?
attempt at the question, i used this equation, G*m1m2/(r1+r2)^2=m1(2pi/T)^2*r1 and furthermore i did, v=r(2pi/T), with this i get r1... but how do i get r2?so that i can get m2 from the above equation of G*m2/(r1+r2)^2=(2pi/T)^2*r1
 
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Did you know the period is the same for both stars?
I was convinced by looking at the animation in Wikipedia (binary stars).
And, of course, the force. Anyway, you can write that
F = 4π²m1*r1/T² = 4π²m2*r2/T².
That gives you 2 equations and 3 unknowns, I think. Maybe use the other formula for the force in the same way to get a 3rd equation?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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