Calculating the Mass of a Gas Molecule Using Kinetic Theory

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SUMMARY

The discussion focuses on calculating the mass of a gas molecule using kinetic theory principles. The provided data includes a temperature of 320 K and a root mean square (rms) molecular speed of 1631 m/s. The relevant equation used is the rms velocity formula, u = √(3RT/M), where R is the gas constant (8.314 J/mol·K). The molar mass of the gas is calculated as M = 3RT/u², leading to a final conversion to kg/molecule using Avogadro's number (6.02e23).

PREREQUISITES
  • Understanding of kinetic theory of gases
  • Familiarity with the ideal gas law
  • Knowledge of the root mean square speed calculation
  • Basic proficiency in unit conversions, particularly from molar mass to molecular mass
NEXT STEPS
  • Study the derivation of the rms speed formula in kinetic theory
  • Learn about the implications of temperature on molecular speed
  • Explore Avogadro's number and its significance in molecular calculations
  • Investigate other gas laws and their applications in real-world scenarios
USEFUL FOR

This discussion is beneficial for physics students, chemistry enthusiasts, and anyone interested in understanding the molecular properties of gases through kinetic theory.

dnl65078
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Homework Statement


A sample of an ideal gas is at a temperature of 320 K. The rms molecular speed at this temperature is measured as 1631 m/s. Calculate the mass of a molecule of this gas


Homework Equations



rms velocity , u = √(3RT/M )

The Attempt at a Solution



Given u = 1631 m / s
Temperature , T = 320 K
R = gas constant = 8.314 J/ mol . K
Molar mass of the gas molecule , M = 3RT / u 2
= 3 * 10^-3 Kg / mol
 
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Right. You can convert to kg/molecule now, or you can use u=sqrt(3kT/m) instead of u=sqrt(3RT/M) and get the answer directly.
 
so do i just multply by 6.02e23?
 

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