- #1

Forco

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## Homework Statement

Find the temperature T that allows the rms speed of a gas to be equal to another gas with T=47°C.

The molecular mass of the first gas is 64, and the molecular mass of the second gas is 32.

## Homework Equations

[tex]v_{rms}= \sqrt{\frac{3RT}{M}}[/tex]

## The Attempt at a Solution

The problem is actually very easy. It's actually really simple to conclude that

[tex]T_1=2T_2[/tex]. However, my problem arises when actually replacing the given temperature.

If I take the second temperature to equal 47°C, then the first temperature is equal to 94°C. And converting that to kelvin gives 367.15 K.

However, if instead I use directly the temperature in K (47+273.15), then my answer becomes 640.3 K.

Which one is right? I assume the second one because in order for the equation to make sense, T needs to be expressed in K. I'd like to be sure, however.