Chemistry Calculating the mass percent from a given volume % and density

AI Thread Summary
The discussion centers on calculating mass percent from volume percent and density, particularly in relation to wine and ethanol solutions. It highlights that while 1 g/mL is a common approximation for water, the density of wine varies due to its sugar content and other substances. A specific example is given with a 12.5% ethanol solution, which has a density of 0.9795 g/mL. The conversation also notes the non-additive nature of volumes when mixing ethanol and water, complicating calculations. Overall, approximate calculations are acceptable, but they inherently carry some error.
CynicusRex
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Homework Statement
A bottle of wine contains 12.5 % ethanol (volume%). The density of ethanol (C2H5OH) is 0.789 g/cm^3. Calculate the concentration of alcohol in wine in: a. mass percent, b. molarity.
Relevant Equations
mass solute a / solution * 100 = mass percent a
p = m/v
[I've solved b, but can't figure out a for the life of me. I have a couple of attempts, but it's just nonsense, it's like I've short circuited.]
 
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Okay, never mind. I didn't know the density of wine/water was 1g/ml.
 
CynicusRex said:
Okay, never mind. I didn't know the density of wine/water was 1g/ml.
It wasn't :wink:

1 g/mL is a rather exact number for water and often a reasonably good approximation for not too concentrated water based solutions, but for better answer you need the density to be measured. 12.5% ethanol solution has a density of 0.9795 g/mL - that can be easily checked in tables. The density of wine is different, as it also contains many other substances, including substantial amount of sugars (which makes the density higher).

Plus, especially in the case of ethanol, calculations are quite difficult, as volumes are not additive - if you mix 50 mL of water with 50 mL of ethanol, you get 96.4 mL of solution.

You are probably expected to do only approximate calculations, but bear in mind they are a bit wrong by definition.
 
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