Calculating the missing resistance when only given voltage

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jacob1995
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Homework Statement


I am asked to calculate the missing resistance(R5) when only given the voltage drop of of 14v across it

Homework Equations


current and divider rule
ohms law

The Attempt at a Solution


[/B]
i tried finding the current of the 6+10 ohm series resistor that is parallel to R5, which would mean they have the same voltage drop. Not sure where i would go from here since i don't know the total resistance, i can't find the total current that is being split between R5 and 6+10 resistor.
 
Attachments
  • Circuit schematic with V2 = 28 V source and resistors R1 = 1 Ω, R2 = 2 Ω, R3 = 4 Ω, R4 = 6 Ω, R5 (unlabelled value), and R6 = 2 Ω.
    Q4.PNG
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Last edited:
jacob1995 said:

Homework Statement


I am asked to calculate the missing resistance(R5) when only given the voltage drop of of 14v across it

Homework Equations


current and divider rule
ohms law

The Attempt at a Solution


[/B]
i tried finding the current of the 6+10 ohm series resistor that is parallel to R5, which would mean they have the same voltage drop. Not sure where i would go from here since i don't know the total resistance, i can't find the total current that is being split between R5 and 6+10 resistor.
Hello,

We would need the actual question with all the information provided to help you. Can you provide more details?
 
nrqed said:
Hello,

We would need the actual question with all the information provided to help you. Can you provide more details?
whoops sorry, reuploaded the circuit
 
jacob1995 said:
whoops sorry, reuploaded the circuit
Ok, thank you.

As a first step, think of the resistors R3, R4 and R5 as a single equivalent resistance, let's call it Req. The voltage across this Req will be 14 volts too. Now, just from the information given, can you determine what must be the value of this Req?
 
nrqed said:
Ok, thank you.

As a first step, think of the resistors R3, R4 and R5 as a single equivalent resistance, let's call it Req. The voltage across this Req will be 14 volts too. Now, just from the information given, can you determine what must be the value of this Req?

3 and 4 are in series, which is in parallel to R5? would i not require current to find the value of Req, since i am missing the value of R5
 
jacob1995 said:
3 and 4 are in series, which is in parallel to R5? would i not require current to find the value of Req, since i am missing the value of R5
What I suggest is to do the problem in two steps. As a first step, it is better to forget completely about R3, R4 and R5. Just call the combination of these three Req. Can you figure out the value of Req? Once you will know that, we will figure out R5.
 
jacob1995 said:
3 and 4 are in series, which is in parallel to R5? would i not require current to find the value of Req, since i am missing the value of R5
Hint: you know the potential of the battery (28 volts), you know the other resistors in the circuit an you know that there is 14 volts across Req. This is enough to find Req.
 
nrqed said:
What I suggest is to do the problem in two steps. As a first step, it is better to forget completely about R3, R4 and R5. Just call the combination of these three Req. Can you figure out the value of Req? Once you will know that, we will figure out R5.

voltage divider rule?
 
jacob1995 said:
voltage divider rule?
Yes, that's one way to do it. Here the numbers given make the calculation very easy.
 
nrqed said:
Yes, that's one way to do it. Here the numbers given make the calculation very easy.
so i got 14 = 28 x Req/ R(1+2+2)
= 2.5?
 
jacob1995 said:
so i got 14 = 28 x Req/ R(1+2+2)
= 2.5?
I am not sure what R(1+2+2) means.

The correct equation is ##14 = \frac{28 R_{eq}}{1+2+2+R_{eq}}##
 
nrqed said:
I am not sure what R(1+2+2) means.

The correct equation is ##14 = \frac{28 R_{eq}}{1+2+2+R_{eq}}##
forgot to add Req back, got a vlaue of 10 for R5
 
jacob1995 said:
forgot to add Req back, got a vlaue of 10 for R5
Good job!