Calculating the missing resistance when only given voltage

  • Thread starter Thread starter jacob1995
  • Start date Start date
  • Tags Tags
    Resistance Voltage
AI Thread Summary
The discussion revolves around calculating the missing resistance (R5) given a voltage drop of 14 volts across it. Participants emphasize using Ohm's law and the voltage divider rule to determine the equivalent resistance (Req) of the resistors in the circuit. The conversation highlights the importance of understanding the relationship between the resistors in series and parallel configurations. After some calculations, the final value of R5 is determined to be 10 ohms. The thread concludes with acknowledgment of the successful resolution of the problem.
jacob1995
Messages
7
Reaction score
0

Homework Statement


I am asked to calculate the missing resistance(R5) when only given the voltage drop of of 14v across it

Homework Equations


current and divider rule
ohms law

The Attempt at a Solution


[/B]
i tried finding the current of the 6+10 ohm series resistor that is parallel to R5, which would mean they have the same voltage drop. Not sure where i would go from here since i don't know the total resistance, i can't find the total current that is being split between R5 and 6+10 resistor.
 

Attachments

  • Q4.PNG
    Q4.PNG
    3 KB · Views: 802
Last edited:
Physics news on Phys.org
jacob1995 said:

Homework Statement


I am asked to calculate the missing resistance(R5) when only given the voltage drop of of 14v across it

Homework Equations


current and divider rule
ohms law

The Attempt at a Solution


[/B]
i tried finding the current of the 6+10 ohm series resistor that is parallel to R5, which would mean they have the same voltage drop. Not sure where i would go from here since i don't know the total resistance, i can't find the total current that is being split between R5 and 6+10 resistor.
Hello,

We would need the actual question with all the information provided to help you. Can you provide more details?
 
nrqed said:
Hello,

We would need the actual question with all the information provided to help you. Can you provide more details?
whoops sorry, reuploaded the circuit
 
jacob1995 said:
whoops sorry, reuploaded the circuit
Ok, thank you.

As a first step, think of the resistors R3, R4 and R5 as a single equivalent resistance, let's call it Req. The voltage across this Req will be 14 volts too. Now, just from the information given, can you determine what must be the value of this Req?
 
nrqed said:
Ok, thank you.

As a first step, think of the resistors R3, R4 and R5 as a single equivalent resistance, let's call it Req. The voltage across this Req will be 14 volts too. Now, just from the information given, can you determine what must be the value of this Req?

3 and 4 are in series, which is in parallel to R5? would i not require current to find the value of Req, since i am missing the value of R5
 
jacob1995 said:
3 and 4 are in series, which is in parallel to R5? would i not require current to find the value of Req, since i am missing the value of R5
What I suggest is to do the problem in two steps. As a first step, it is better to forget completely about R3, R4 and R5. Just call the combination of these three Req. Can you figure out the value of Req? Once you will know that, we will figure out R5.
 
jacob1995 said:
3 and 4 are in series, which is in parallel to R5? would i not require current to find the value of Req, since i am missing the value of R5
Hint: you know the potential of the battery (28 volts), you know the other resistors in the circuit an you know that there is 14 volts across Req. This is enough to find Req.
 
nrqed said:
What I suggest is to do the problem in two steps. As a first step, it is better to forget completely about R3, R4 and R5. Just call the combination of these three Req. Can you figure out the value of Req? Once you will know that, we will figure out R5.

voltage divider rule?
 
jacob1995 said:
voltage divider rule?
Yes, that's one way to do it. Here the numbers given make the calculation very easy.
 
  • #10
nrqed said:
Yes, that's one way to do it. Here the numbers given make the calculation very easy.
so i got 14 = 28 x Req/ R(1+2+2)
= 2.5?
 
  • #11
jacob1995 said:
so i got 14 = 28 x Req/ R(1+2+2)
= 2.5?
I am not sure what R(1+2+2) means.

The correct equation is ##14 = \frac{28 R_{eq}}{1+2+2+R_{eq}}##
 
  • #12
nrqed said:
I am not sure what R(1+2+2) means.

The correct equation is ##14 = \frac{28 R_{eq}}{1+2+2+R_{eq}}##
forgot to add Req back, got a vlaue of 10 for R5
 
  • #13
jacob1995 said:
forgot to add Req back, got a vlaue of 10 for R5
Good job!
 
  • #14
nrqed said:
Good job!
thank you for the help
 

Similar threads

Replies
3
Views
2K
Replies
2
Views
1K
Replies
18
Views
3K
Replies
1
Views
2K
Back
Top