Calculating the Momentum of Oxygen Molecules at 484 m/s

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SUMMARY

The momentum of an oxygen molecule traveling at a speed of 484 m/s is calculated using the formula p=mv, where the molar mass of oxygen (M) is 0.032 kg/mole and Avogadro's number (Na) is 6.022 x 10^23. The correct mass (m) of a single oxygen molecule is derived as M/Na, leading to a momentum value of 2.57 x 10^-13 kg·m/s. The confusion arose from a miscalculation that resulted in an incorrect value of 2.57 x 10^-23, which was clarified as erroneous.

PREREQUISITES
  • Understanding of momentum calculation using the formula p=mv
  • Knowledge of molar mass and Avogadro's number
  • Basic familiarity with unit conversions in physics
  • Ability to perform scientific notation calculations
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  • Study the derivation of momentum in classical mechanics
  • Learn about Avogadro's number and its applications in chemistry
  • Explore the concept of molar mass and its significance in molecular calculations
  • Investigate common pitfalls in scientific notation and precision in calculations
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Students and professionals in physics and chemistry, particularly those focusing on molecular dynamics and momentum calculations.

Punkyc7
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What is the momentum of an oxygen molecule traveling at this speed?

the speed was 484 m/s

the molar mass of oxygen is M=.032 kg/mole

Na= 6.022 x10^23
I do p=mv

v=484
m=M/Na

The answer should be 2.57x10^-13 but i keep getting 2.57 x10^-23
 
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Check your calculations again, your operations are correct.
 
I still get 2.57 x 10^-23
 
Your result is correct.

ehild
 
So the solution in the book is wrong, Thank you
 
Last edited:

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