Calculating the Momentum of Oxygen Molecules at 484 m/s

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Homework Help Overview

The discussion revolves around calculating the momentum of oxygen molecules, specifically focusing on a speed of 484 m/s and the molar mass of oxygen. Participants are examining the relationship between mass and velocity in the context of momentum.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate momentum using the formula p=mv, questioning their results based on differing outcomes. Some participants suggest re-evaluating calculations, while others confirm the correctness of the original poster's operations.

Discussion Status

The discussion is ongoing, with participants verifying calculations and expressing differing results. There is no explicit consensus on the accuracy of the final answer, but some guidance has been offered regarding the calculation process.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can use. There is also a mention of a potential discrepancy with a solution provided in a textbook.

Punkyc7
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What is the momentum of an oxygen molecule traveling at this speed?

the speed was 484 m/s

the molar mass of oxygen is M=.032 kg/mole

Na= 6.022 x10^23
I do p=mv

v=484
m=M/Na

The answer should be 2.57x10^-13 but i keep getting 2.57 x10^-23
 
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Check your calculations again, your operations are correct.
 
I still get 2.57 x 10^-23
 
Your result is correct.

ehild
 
So the solution in the book is wrong, Thank you
 
Last edited:

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