Calculating the power output from a persons mouth

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Homework Help Overview

The problem involves calculating the power output from a person's mouth based on the sound level measured at a distance. The subject area pertains to acoustics and sound intensity, specifically relating to the concepts of sound power and intensity in decibels.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the area over which the sound spreads and expresses difficulty in determining the intensity from the given sound level in decibels. Some participants reference external sources to provide context on sound power and suggest that the original poster should focus on the relationship between sound intensity and decibels.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem. Some guidance has been offered regarding the relationship between sound levels and intensity, but there is no explicit consensus on the approach to take. Questions about the relevance of particle velocity in the context of the problem have also been raised.

Contextual Notes

Participants are navigating the complexities of converting sound levels in decibels to intensity, with some uncertainty about the appropriate equations and assumptions needed for the calculations. The original poster has expressed a lack of clarity on how to proceed with the information provided.

Aleisha
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Homework Statement


Speech at a distance of 45.1 cm has a sound level of 59.3 dB. Assuming that the energy in the sound spreads out equally in all directions from the person's mouth, calculate the total power output from the person.

Given:
Distance= 0.451m
Sound level 59.3 dB
P=? J

Homework Equations


I=P/A
A=4 x Pi x r^2

The Attempt at a Solution


A= 4 x Pi x 0.451^2
= 2.5560 m^2

I tried to find I (Intensity) by rearranging the; dB=10 log (I/Io) but isn't possible... So I'm a little stuck as to how to calculate the Intensity so I can substitute into the I=P/A equation. I know somehow I must use the given decibels at some point but I've been looking for an equation but can't find it.

Much appreciate if someone could help, thank you :)
 
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One reference that I googled up is https://en.wikipedia.org/wiki/Sound_power.

The relevant information is given in this passage:

For example, a sound at SPL = 85 dB or p = 0.356 Pa in air (ρ = 1.2 kg·m−3 and c = 343 m·s−1) through a surface of area A = 1 m2 normal to the direction of propagation (θ = 0 °) has a sound energy flux P = 0.3 mW

I would ignore the table at the top of that article. It does not have the appropriate units for your application -- it is reporting a distance-independent quantity.
 
Am i assuming that the particles are moving at a velocity of v=343m/s?
 
Aleisha said:
Am i assuming that the particles are moving at a velocity of v=343m/s?
I do not see how particle velocity comes into it. If you have a power flux for 85db in milliwatts per square meter, that gives you enough information to compute a power flux for 59.3 db in milliwatts per square meter.
 

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