Calculating the power required to move a load up a gradiant

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To calculate the power required for a cart to move a 40 kg load up a 14-degree incline at speeds between 1-4 MPH, the relevant equation is P = M x G x SIN(Angle) x V. The initial calculation yields approximately 169 watts, which is equivalent to about a quarter horsepower. However, considering motor inefficiencies, it is recommended to use a motor rated at half a horsepower for optimal performance. This ensures adequate power to handle variations in load and incline. Accurate calculations are essential for effective system design.
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HI

Any help with this problem would be much appreciated.

I am designing a system in which a cart type machine needs to be able to carry a load up a hill with almost no help from the person pushing, My question is how do I calculate how much power is needed by the motor to move the load.

I know:
Total Load = 40KG
Maximum Incline = 14Degrees
The speed it will travel between is 1-4 MPH


I believe the relevant equations are P=MxGxSIN(Angle)xV
Also I am not sure but J=FxD

D=Distance
F=Force
J=Joules
M=Mass
G=Gravity
V=Velocity
P=Power

I believe its 40x9.81xSin14x1.78m/s = 169w

I just want to make sure this equation is right and if not what equation I need to use. it would be handy to have an equation as the variables are constantly changing.

Many thanks in advance for your help.
 
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Looks OK to me, at 4 mph max speed. 169 w is about a quarter horsepower. Due to inefficiencies in the motor, I'd opt for a half a horse motor.
 

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