Calculating the probability of winning the lotto

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The probability of winning the 6/49 lotto is calculated as P(L) = 1 / 13,983,816, meaning that if one plays once a year, they would statistically win once every 13,983,816 years. If playing daily, the average wait time increases to approximately 268,920 years, derived from dividing the total plays per win by the frequency of play (13,983,816 / 52). The discussion highlights the importance of understanding units of time and frequency in probability calculations, emphasizing that the expected number of plays until a win is crucial for accurate estimations.

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trap101
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So I have a question I was going over in a textbook about calculating the probability of winning the 6/49 lotto. Which means you have to pick 6 correct numbers out of 49, order does not matter. So I got that:

P(L) = 6/49 * 5/48* 4/47 * ...* 1/44 = 1 / 13,983816

but then there is a comment afterwards that I can't figure out the solution:

"So if you were to play once a year, on the average you would win once every 13,983,816 years. If you played once per day, given that there are 364.25 days in a year,on average you would win once every 268,920 years.

How do they obtain the 268,920 years? What am I missing in being able to convert it over?

Thanks
 
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hi trap101! :smile:
trap101 said:
"So if you were to play once a year, on the average you would win once every 13,983,816 years. If you played once per day, given that there are 364.25 days in a year,on average you would win once every 268,920 years.

13,983,816 / 268,920 = 51.9999

sooo :rolleyes: … i guess they meant once a week! :wink:
 
tiny-tim said:
hi trap101! :smile:


13,983,816 / 268,920 = 51.9999

sooo :rolleyes: … i guess they meant once a week! :wink:

Thanks Tim, but I'm still not clearly getting it. So dividing those two sets of years provides me with 51.99, which I suppose means 52 weeks. I think I'm getting confused with which unit where.
 
trap101 said:
Thanks Tim, but I'm still not clearly getting it. So dividing those two sets of years provides me with 51.99, which I suppose means 52 weeks. I think I'm getting confused with which unit where.

The expected number of times you must play until you win is 13,983,816. If you played once a year, then on average you would need to wait about 13 million years until you win. If you played once per week (52 times per year) you would need to wait about 13,983,816/52 ≈ 269,000 years, etc.
 
hi trap101! :smile:

(just got up :zzz:)
trap101 said:
I think I'm getting confused with which unit where.

since you're asking about units, i'll just add to what Ray :smile: says …

the units are plays per win (or play.win-1)

the question asks about time per win,

so you multiply plays per win * time per play (= time per win) …

the lotto always has a play per win of 13,983,816

if time per play is 1 year, then time per win = 13,983,816*1 years

if time per play is 1/52 year (ie 1 week), then time per win = 13,983,816*1/52 years :wink:
 
tiny-tim said:
hi trap101! :smile:

(just got up :zzz:)


since you're asking about units, i'll just add to what Ray :smile: says …

the units are plays per win (or play.win-1)

the question asks about time per win,

so you multiply plays per win * time per play (= time per win) …

the lotto always has a play per win of 13,983,816

if time per play is 1 year, then time per win = 13,983,816*1 years

if time per play is 1/52 year (ie 1 week), then time per win = 13,983,816*1/52 years :wink:




Ahhh. Thank you gentlemen. It really comes down to documenting every aspect so I could get these unit troubles under control.
 

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