Calculating the Required Force to Prevent Sliding on an Incline Plane

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Homework Help Overview

The problem involves two objects on an inclined plane, where one object with a larger mass is positioned lower down, and a smaller mass is leaning on the larger mass. The task is to determine the required force to prevent the smaller mass from falling, given the angle of the incline, coefficients of static and kinetic friction, and the masses involved.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to analyze the forces acting on both blocks, using equations of motion and friction. Some participants question the clarity of the setup, particularly the positioning of the smaller mass and the relevance of the coefficient of kinetic friction. Others suggest treating the blocks as a system rather than separately.

Discussion Status

The discussion is ongoing, with participants providing insights into the interpretation of the problem and the setup. There is a recognition of the need for clarity regarding the arrangement of the masses and the forces involved. Some guidance has been offered regarding the treatment of the blocks as a system.

Contextual Notes

There is uncertainty about the physical arrangement of the blocks, which may affect the analysis. The necessity of the coefficient of kinetic friction in this context is also under scrutiny, as the goal is to prevent movement.

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Homework Statement



Two objects are on an incline plane. One object with larger mass is lower down on the plane. The other with smaller mass is leaning on the larger object but not one the surface of the plane. If both masses, the angle β, coefficient of static friction and the coefficient of kinetic friction are given what is the required Fa to keep the second block from falling.

Homework Equations


The Attempt at a Solution



I've been working on this for several hours but have been unable to figure out the solution. What I tried doing was starting with the second block which I will call m.

Fnety = ma = 0
Fstatic friction - mgcosβ = 0
Fstatic = mg cosβ
[tex]\mu[/tex]Fn=mgcosβ
Fn=mgcosβ/[tex]\mu[/tex]

Fnet x = ma = mgcosβ/[tex]\mu[/tex] - mgsingβ
a = gcosβ/[tex]\mu[/tex]k - gsinβ

Then for both blocks combined I did

Fnety = ma = 0
Fn - (M+m)gcosβ = 0
Fn = (M+m)gcosβ

Fnetx = Fa - Fkinetic friction = (M+m)a
Fa = [tex]\mu[/tex]s(M+m)gcosβ + (M+m)(gcosβ[tex]\mu[/tex]k - gsinβ)

This is the answer I got but my teacher told me its wrong, can anyone give me some help as to where I am messing it up
 
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I don't understand the set-up, and I doubt that I'm the only one, could you explain it more or give a diagram? I don't understand where the smaller mass is. Is it on top of the the other mass? If not, how is it resting on the plane without being in contact with the plane, by rollers or something? How the smaller block is resting is very critical.

Another thing that I don't understand from the problem description is why you would need the coefficient of kinetic friction. The whole point is for the blocks not to move.
 
The photo I attached is of the given diagram. The smaller mass is leaning on the larger mass but above the ground. The coefficient of static and kinetic were given, I assumed the static was for between the two masses and the kinetic was for between the larger mass and the plane.
 

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Treat the two blocks as a system, don't split it up. So I guess what you want to do is figure out what force in addition to static friction will prevent the blocks from sliding. I agree with most of what you've done in that case; however, the normal force should not have both masses, but the force of gravity should. Then make an inequality showing that the applied force must be greater than or equal to your result.
 

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