Calculating the Speed of a Cricket Ball with Drag Force: Homework Problem

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SUMMARY

The discussion focuses on calculating the speed of a cricket ball as it travels towards the wicket, factoring in drag force. The initial speed of the ball is 151 km/h, and the drag force is modeled by R = kmv², where the drag coefficient is assumed to be 0.3. The participant attempted to solve the problem using the equation R = 0.5DpAv² but struggled with determining the drag coefficient. Ultimately, they calculated the speed at the wicket to be approximately 133 km/h.

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Homework Statement



At international cricket games, it is commonplace to display on the scoreboard a speed for each bowl. Because the ball is subject to a drag force due to air proportional to the square of its speed given by R = kmv^2, it slows as it travels 20 m toward the wicket according to the formula v = vie^(−kx). Suppose the ball leaves the bowler's hand at 151 km/h. Ignore its vertical acceleration, and determine the speed of the ball when it hits the wicket. (For a cricket ball, assume the mass is 0.16 kg, the radius is 3.5 cm, and the terminal velocity is 40 m/s. The density of air is 1.2 kg/m3.)

Homework Equations



Apart from the equations i have tried R=0.5DpAv^2
but i don't know the drag coefficient!

The Attempt at a Solution


Honestly i don't know where to start, i have tried googling a similar question also.
The problem is I cannot figure out R. If i knew drag coefficient i could work out k, then work out v over the distance
 
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What is the drag force at the termimal velocity? You can work out "k" using that information.
 
I worked drag force R out with R = -bV and using the above formal for R with a drag coefficient of .3 which i found online. Both gave a similar result. I got 133km/h
 

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