Distance of projectile - only speed given

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Homework Help Overview

The problem involves calculating the maximum distance a projectile could be thrown given an initial speed of 159.5 km/h, with considerations for vertical and horizontal trajectories. The context is projectile motion, specifically examining the effects of gravity and the assumptions made about the motion of the ball.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to clarify the meaning of "maximum distance" and whether it refers to vertical height or horizontal distance. There are questions about the constancy of velocity and the effects of gravity on the projectile's motion. Some participants suggest using equations of motion, while others express confusion about deriving necessary values such as time and acceleration.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and raising questions about missing information. Some guidance has been offered regarding the use of equations of motion and the implications of gravity, but no consensus has been reached on how to proceed due to ambiguities in the problem statement.

Contextual Notes

Participants note that the problem lacks specific details, such as the height from which the ball is thrown, which complicates the calculations for both vertical and horizontal trajectories. There is also uncertainty about the interpretation of "maximum distance."

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Homework Statement


Andy Roberts the former West Indian Cricket player and Fast Bowler, bowled his fastest delivery in 1975 at 159.5 km/h. Neglecting air resistance, calculate the maximum distance he could have thrown the ball at this speed (on earth!) had he been able to throw it:

i) Vertically upwards from the cricket field

ii) Horizontally across the cricket field.

Homework Equations


s=ut+1/2at^2
v=u + at (rearranged for a and t)
distance = speed x time

The Attempt at a Solution


I'm pretty confused with this problem - I'm used to a couple of values being given with equations of motion and projectiles. I was wondering whether to find the acceleration of the ball or to just assume that it's constant? The value given is a velocity with it having a direction (horizontal / vertical) making it a vector right?

I'm not sure whether the velocity stays constant throughout either? If it's being thrown the maximum distance then it's bound to lose velocity as time progresses. How am I to calculate this for the final velocity and how would this impact on the time?

Converting the 159.5 km/h to metres per second gives 44.31 m/s. This will be the initial velocity but how to find the acceleration and time values? I'm sure gravity comes into it for the horizontal as well as vertical directions and I imagine the ball won't be airborne for more than 3-5 seconds or so but how to calculate the certainty?

I was looking into using a speed - time graph and finding distance from the area underneath but again there aren't enough values given and I don't know how to derive them.

Thanks
 
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Day3091 said:
Neglecting air resistance, calculate the maximum distance he could have thrown the ball at this speed (on earth!) had he been able to throw it:
The problem is oddly worded, but I interpret it as: What's the maximum height the ball could be thrown? and: What's the maximum distance across the field the ball could be thrown?

Day3091 said:
I'm not sure whether the velocity stays constant throughout either?
If the velocity stayed constant the ball would just keep going higher and higher!

Hint: This is a projectile motion problem.
 
I need to find the time in seconds for the vertical trajectory and then I can multiply that by the 44.31 m/s for the horizontal distance.

I'm stuck with how to find the vertical time or distance though. I'm sure it's derived from s=1/2at^2 and for time this would be rearranged to:

t^2= 2s/a and then square rooting.

Would there be an acceleration for the vertical path with gravity acting down on the ball? In most of the example problems I'm reading about there is always at least one more value given.
 
The question is very badly worded...

a) If he throws it straight up the ball will start decelerating at "g" as soon as it leaves his hand. To calculate how high it will go you can either apply conservation of energy or use the equations of motion with constant acceleration. It's not clear what "maximum distance" means. Is it the vertical height achieved? Double that? or zero because it lands back where it starts.

b) If he throws it horizontally you need to know how tall he is in order to calculate the time it take to fall to the ground. That's not given so you cannot answer this question without making an assumption about his height.

Day3091 said:
I need to find the time in seconds for the vertical trajectory and then I can multiply that by the 44.31 m/s for the horizontal distance.

Lets assume there is a part c) that asks how far he could throw the ball if given a choice of launch angles..

It can be shown that the max range is achieved with a 45 degree launch angle. This is then a projectile motion problem. You need to calculate the horizontal and vertical components of the launch velocity. The vertical component and the equations of motion give you the time of flight. That and the horizontal component of velocity gives you the range.
 
Firstly, there are some issues about your problem, could you please just copy-paste the problem here?

The main issues are:
1) what's the "maximum distance", you should be able to tell us if we are talking about the displacement on the x axis, the y-axis or both of them
2) Reading you problem, it is not possible to answer part of it with just the data you provided.

Again, please re-read the problem carefully and just copy-paste it here if you need help, I'm pretty sure that you either read the questions wrongly or missed some data "kind of hidden" in the problem statement
 

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