Calculating the Speed of a Seagull Diving for Clams in 3.32 Seconds

[Quevvy]

1. A seagull diving towards a stone beach at an angle of 60 degrees to the vertical releases a clam from a height of 100 meters. The clam hits the beach 3.32 seconds later. To the nearest tenth of a m/s what was its speed when it was released?



2. v=v_0 + a*t

 

[rl.bhat]

If v is the velocity of seagull when it releases the clam, find the horizontal and vertical components of v.
Height is given, time is given and g is known.
Use the proper kinematic equation to find vy.
From that you can find vx.
required answer is vx*t.

 

[Quevvy]

If v is the velocity of seagull when it releases the clam, find the horizontal and vertical components of v.
Height is given, time is given and g is known.
Use the proper kinematic equation to find vy.
From that you can find vx.
required answer is vx*t.

Thanks, I think that I got it now