I need someone to help me find the answer to this difficult homework problem: A seagull is diving towards a stone beach at an angle of 60 degrees to the vertical releases a clam from a height of 100 meters. The clam hits the beach 3.02 seconds later. To the nearest tenth of a m/s what was its speed when it was released?
I tried vi= m/s/sin(theta), r=2(vi^2/G)sin(60)cos(60)...???help?!?
I tried vi= m/s/sin(theta), r=2(vi^2/G)sin(60)cos(60)...???help?!?