Calculating the Surface Area of a Sphere: How Does it Differ?

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Discussion Overview

The discussion revolves around the calculation of the surface area of a sphere, particularly focusing on the interpretation of the formula and its application in spherical coordinates. Participants express confusion regarding the mathematical representation and the meaning of certain terms.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • Some participants express confusion about the meaning of specific mathematical terms, indicating a lack of clarity in the discussion.
  • One participant asserts that the area on a two-dimensional manifold is a 2-form, not a 1-form, suggesting a conceptual distinction in the mathematical framework.
  • Another participant clarifies that the formula discussed represents the area of a circular band on the sphere, providing a reference image for context.
  • A participant provides the differential area formula in spherical coordinates, stating that integrating over this formula leads to a specific expression for the area of a circular band.
  • There is acknowledgment of helpfulness from some participants, indicating that the discussion has provided some clarity despite initial confusion.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the interpretation of the mathematical terms and concepts, with multiple viewpoints expressed regarding the nature of the area calculation.

Contextual Notes

Some limitations include potential misunderstandings of mathematical terminology and the dependence on specific definitions of forms in the context of differential geometry.

AyoubEd
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please , I'm french , so i didn't quite get the meaning of this sentence.
 

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I also have not got it . Area on two dimensional manifold is a 2-form not 1-form
 
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it's confusing and wasting my time :frown:.
thank you anyway.
 
Yes Nasu has got it right, the differential area of a sphere in spherical coordinates is:

##dA = R^2 sin \theta d\theta d\phi##

and integrating over ##d\phi##

and then setting R=1 you get

##Aring = 2\pi * sin \theta d\theta##
 
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Thanks a lot guys.
that was very helpful
 

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