Calculating the time of stopping distance

[chaz699]

well I'm struggling with a level physics and need some help with a new topic area we're studying

the problem is

a moving car t velocity of 20 ms(-1) brakes to a standstill in a distance of 40m, a child of mass 15kg is sitting in a forward facing child car seat fitted to the back-seat of the car

calculate (1) the deceleration (2) the force on the child


i always thought to calculate the deceleration is braking distance/ mass but the only mass given is that of the child and surely the car will way more than that, hence why i don't understand what formula to use, is it using suvat? if so i can't find a suvat formula with only s U and v, its driving me mad ( no pun intended)



for the second part of the question I haven't been told any information on how to work it out but is the formula t= 2s/U + v (t is time, s is distance/displacement, U is initial velocity and v is final velocity

 

[PhanthomJay]

well I'm struggling with a level physics and need some help with a new topic area we're studying

the problem is

a moving car t velocity of 20 ms(-1) brakes to a standstill in a distance of 40m, a child of mass 15kg is sitting in a forward facing child car seat fitted to the back-seat of the car

calculate (1) the deceleration (2) the force on the child


i always thought to calculate the deceleration is braking distance/ mass but the only mass given is that of the child and surely the car will way more than that, hence why i don't understand what formula to use, is it using suvat? if so i can't find a suvat formula with only s U and v, its driving me mad ( no pun intended)

I don't know why you were thinking that distance/mass equals acceleration. Erase that thought. What about the kinematic equation vf^2 = vo^2 + 2as? You didn't do enough searching on your suavat's.

for the second part of the question I haven't been told any information on how to work it out but is the formula t= 2s/U + v (t is time, s is distance/displacement, U is initial velocity and v is final velocity

How about using Newton's 2nd law?

 

[chaz699]

i think i have it now

thanks (i found out Newtons second law about 2 minutes before u posted, and the suvat question i just found,) thanks for providing me with support so i avoidied doubting myself