Calculating the Total Work Done by Gravity

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Homework Help Overview

The problem involves calculating the total work done by gravity on a satellite fragment that falls to Earth after being ejected from a satellite in orbit. The context includes gravitational potential energy and the effects of gravity on an object transitioning from orbit to ground impact.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of gravitational potential energy and the change in energy as the fragment falls. There are attempts to simplify the algebra involved and check for errors in orders of magnitude.

Discussion Status

Some participants have offered guidance on checking calculations and suggested a symbolic approach to the energy difference. There is acknowledgment of potential errors in unit conversion and orders of magnitude, with participants exploring these aspects without reaching a consensus on the final calculation.

Contextual Notes

There is a noted issue with unit conversion, specifically regarding the radius of the Earth, which has led to confusion in calculations. Participants are also reflecting on the implications of their assumptions and the setup of the problem.

Simon777
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Homework Statement


A satellite in a circular orbit around the Earth with a radius 1.011 times the mean radius of the Earth is hit by an incoming meteorite. A large fragment (m = 83.0 kg) is ejected in the backwards direction so that it is stationary with respect to the Earth and falls directly to the ground. Its speed just before it hits the ground is 355.0 m/s. Find the total work done by gravity on the satellite fragment. RE 6.37·10^3 km; Mass of the earth= ME 5.98·10^24 kg.


Homework Equations


Gravitational PE= (-GmM)/R

The Attempt at a Solution



Delta PE= PE intial - PE final

= (-(6.67x10^-11) (83kg) (5.98x10^24kg))/((1.011) (6.37x10^3)) - (-(6.67x10^-11) (83kg) (5.98x10^24kg))/(6.37x10^3)

= 5.65x10^10J

This is incorrect and I have tried for hours to get something to work so any help would be greatly appreciated.
 
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Something happened to your orders of magnitude. I think you're result is about 1000x to big. Check your math.

You can save yourself a lot of digit pushing if you do some of the algebra symbolically ahead of time:

Let r = 1.011; M = Mass of Earth; R = radius of Earth; m = mass of fragment;

\Delta E = \left(\frac{G M m}{R} - \frac{G M m}{r R}\right) = \frac{G M m}{R}\left(1 - \frac{1}{r}\right)
 
gneill said:
Something happened to your orders of magnitude. I think you're result is about 1000x to big. Check your math.

You can save yourself a lot of digit pushing if you do some of the algebra symbolically ahead of time:

Let r = 1.011; M = Mass of Earth; R = radius of Earth; m = mass of fragment;

\Delta E = \left(\frac{G M m}{R} - \frac{G M m}{r R}\right) = \frac{G M m}{R}\left(1 - \frac{1}{r}\right)

That does make it easier, thank you. Using it, I still end up with 5.65x10^10J. Perhaps one of my terms is wrong. This is what I used:
M=5.98·10^24 kg
G=6.67x10^-11
m=83.0kg
R= 6.37·10^3 km
r= 1.011
 
Convert your Earth radius to meters!
 
gneill said:
Convert your Earth radius to meters!

I can't believe I wasted all that time because I overlooked something so basic as units. Thank you so much for helping me realize this. I was over thinking it and thought I needed to factor something else in.
 

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