Calculating the x-component of a vector with magnitude and direction

[ymehuuh]

The magnitude of vector A is 35.1 units and points in the direction 301° counterclockwise from the positive x-axis. Calculate the x-component of this vector.

So...35.1=sqrt(vx^2 + vy^2)

and 301°= vy/vx

How do I do this?

 

[hage567]

You just need trig. It's a right angled triangle. You know an angle and the hypotenuse, so what can you do to find the x component?

 

[ymehuuh]

Wow. It was that easy. Thanks.