Calculating Thermal Energy Dissipated from Brakes on a Descending Car

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SUMMARY

The discussion focuses on calculating the thermal energy dissipated from the brakes of a 1260-kg car descending an 18.5° hill. The car, initially traveling at 102 km/h, decelerates to 34 km/h over a distance of 0.51 km. The work-energy theorem is essential for this calculation, as it states that the work done by the brakes equals the mechanical energy lost, which primarily converts to thermal energy.

PREREQUISITES
  • Understanding of the work-energy theorem
  • Knowledge of potential and kinetic energy calculations
  • Familiarity with basic physics concepts related to energy conversion
  • Ability to perform unit conversions (e.g., km/h to m/s)
NEXT STEPS
  • Calculate potential energy change using the formula PE = mgh
  • Determine kinetic energy at initial and final speeds using KE = 0.5mv²
  • Apply the work-energy theorem to find the work done by the brakes
  • Convert the work done into thermal energy dissipated
USEFUL FOR

This discussion is beneficial for physics students, automotive engineers, and anyone interested in understanding the thermal dynamics of braking systems in vehicles.

Stryder_SW
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Homework Statement


Proper design of automobile braking systems must account for heat buildup under heaving braking. Calculate the thermal energy dissipated from brakes in a 1260-kg car that descends a 18.5° hill. The car begins braking when its speed is 102 km/h and slows down to a speed of 34 km/h in a distance of 0.51 km measured along the road.


I honestly have no idea how to do this.
 
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Think about how much potential energy as well as kinetic energy must be accounted for by the work of breaking over that distance.
 
Hi Stryder_SW! :smile:

Virtually all the mechanical energy lost goes into heat (thermal energy), so …

Hint: use the work-energy theorem … work done by the brakes = mechanical energy lost. :wink:
 

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