Calculating thermal kinetic energy of a liquid.

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SUMMARY

The calculation of thermal kinetic energy for liquids follows the same principle as for gases, utilizing the formula (3/2)kT, where k represents the Boltzmann constant and T is the temperature. This is supported by the equipartition theorem, which states that each quadratic degree of freedom contributes 1/2 kT to the energy. However, this classical approach does not hold in quantum mechanics, where the energy of a quantum harmonic oscillator differs significantly. In liquids, interactions between particles must also be considered, complicating the analysis beyond classical methods.

PREREQUISITES
  • Understanding of classical statistical mechanics
  • Familiarity with the equipartition theorem
  • Knowledge of quantum mechanics principles
  • Basic concepts of thermodynamics
NEXT STEPS
  • Study the equipartition theorem in detail
  • Explore classical vs. quantum statistical mechanics
  • Learn about quantum harmonic oscillators and their energy states
  • Investigate the effects of particle interactions in liquids
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Students and professionals in physics, particularly those focused on thermodynamics, statistical mechanics, and quantum mechanics, will benefit from this discussion.

Alex319
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I want to know, given a liquid at a particular temperature and pressure, how fast the atoms in it are moving due to thermal motion. I know that you can do this by calculating the thermal kinetic energy of the atoms, and then figure out the speed from there.

I also know that for gases the formula is (3/2)kT, but is the same true for liquids? If not, then what is the formula?
 
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Yes, the same is true for liquids.

It's because the kinetic energy term is quadratic in momentum and can always be factored out of the total partition function- Q=Q(KE) * Q(PE)

Any quadratic degree of freedom has an energy of 1/2 k T, a result generally referred to as the equipartition theorem.

However, the 1/2 kT rule is only true in classical statistical mechanics. It is not true in a quantum analysis.

For example, a quantum harmonic oscillator in its ground state has energy E=1/2 hbar w0, with K.E.=1/4 hbar w0, which is not equal to 1/2 kT.
 
I think you could easily show that the average kinetic energy is proportional to T, but in liquids particularly, you can't neglect the interactions of the various liquid particles. Again, as christian said, this is for the classical method.
 

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