Calculating theta(t): Mass, M & B Variables

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To calculate theta(t) for a balanced system with a lower mass that increases as m(t) = Bt, the angle is derived as theta(t) = arccos((Bt)/M). The initial conditions state that the lower mass starts at zero and theta is initially 90 degrees. There is some confusion regarding the reference angle for gravity, as it typically relates to the ground level rather than the ramp's top. The solution appears correct, despite the unique angle consideration. Understanding the angle's context is crucial for accurate calculations in similar problems.
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Homework Statement



See the Question Below For Diagram

In the diagram below, calculate theta(t) such that the system remains balanced. The mass of the lower mass is initially zero and theta is initially 90 degrees, but water is poured into the lower mass such that m(t) = Bt. Answer in terms of M and B.

Homework Equations





The Attempt at a Solution



I was just wondering if my work was right. I got theta(t) = arccos((Bt)/M). I'm sort of unsure if I got the angle correct for the x component of gravity sense normally the angle that we are concerned with is level with the ground and at the bottom of the ramp and not the top.
 

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Good observation. Your answer looks good!
 
Alright thanks I wasn't sure because I never solved a problem like that before were the angle I was concerned with was not the one that was on the ground.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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