Calculating theta(t): Mass, M & B Variables

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SUMMARY

The discussion focuses on calculating the angle theta(t) for a system in equilibrium, where the mass of the lower mass increases over time as water is added, represented by the function m(t) = Bt. The derived formula for theta(t) is arccos((Bt)/M), where M is the constant mass and B is the rate of water addition. Participants confirmed the correctness of the angle calculation, emphasizing the importance of considering the angle relative to the ground rather than the ramp's top.

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Homework Statement



See the Question Below For Diagram

In the diagram below, calculate theta(t) such that the system remains balanced. The mass of the lower mass is initially zero and theta is initially 90 degrees, but water is poured into the lower mass such that m(t) = Bt. Answer in terms of M and B.

Homework Equations





The Attempt at a Solution



I was just wondering if my work was right. I got theta(t) = arccos((Bt)/M). I'm sort of unsure if I got the angle correct for the x component of gravity sense normally the angle that we are concerned with is level with the ground and at the bottom of the ramp and not the top.
 

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Good observation. Your answer looks good!
 
Alright thanks I wasn't sure because I never solved a problem like that before were the angle I was concerned with was not the one that was on the ground.
 

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