Calculating Time Evolution of Density Matrix

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To calculate the time evolution of a density matrix for a mixed state, it is acceptable to use the evolved kets, such as |x,t> = e^(-i/h Ht) |x,0>. However, it is crucial to also consider the Hermitian conjugate, which is <x,t| = <x,0| e^(i/h Ht). This ensures that the density matrix evolves correctly over time according to the unitary time evolution equation, rho(t) = U rho(0) U-dagger. The unitary operator U is defined as e^(-i/hbar H t). Properly applying these principles will yield an accurate time-evolved density matrix.
dg88
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Hi,

I am trying to calculate the time evolution of a density matrix. Like if there is a mixed state with 50% of |x, 0> and 50% of |y, 0>. After time t due to time evolution, the kets become:

|x,t>= e^(-i/h Ht) |x,0> and so on.

Is it ok to use these kets instead of the original ket to calculate the density matrix after time t? Or is there another method to do it?
 
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dg88 said:
Hi,

I am trying to calculate the time evolution of a density matrix. Like if there is a mixed state with 50% of |x, 0> and 50% of |y, 0>. After time t due to time evolution, the kets become:

|x,t>= e^(-i/h Ht) |x,0> and so on.

Is it ok to use these kets instead of the original ket to calculate the density matrix after time t? Or is there another method to do it?

Yes, but don't forget to take the Hermitian conjugate:

<x,t| = <x,0| e^(i/h Ht)

So, you see that if you do this the density matrix evolves in time according to the unitary time evolution:

rho(t) = U rho(0) U-dagger

U = e^(-i/hbar H t)
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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