Resistance of a water heaters heating element?

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Homework Help Overview

The discussion revolves around calculating the resistance of a water heater's heating element, given a specific scenario involving heating water from one temperature to another. The subject area includes concepts from electricity and thermodynamics, particularly focusing on current, resistance, and specific heat.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between electrical power, current, and thermal energy. There are attempts to connect the concepts of specific heat and the energy required to heat water to the electrical parameters needed for the problem.

Discussion Status

The discussion is ongoing, with participants raising questions about specific heat and its relation to the problem. Some guidance has been provided regarding the calculation of power and the conversion of heat energy into electrical terms, but no consensus has been reached on the overall approach.

Contextual Notes

Participants note the need for clarity on how to relate different units and concepts, including the specific heat of water and the conversion of gallons to kilograms. There is an acknowledgment of the chapter's focus on current and resistance, which may influence the understanding of the problem.

Rijad Hadzic
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Homework Statement


Household water heaters use a 240 V rather than a 120 V source. What is the resistance of a water heater's heating element if it heats 40 gallons (151 kg) of water from 15 C to 60 C in 15 min

Homework Equations


P = IV
P = I^2R
I = dq/dt

The Attempt at a Solution


Honestly no clue. If anyone can give me some hints I would really appreciate this.

So far I have electrical units, V, and then I have kg, celsius, and seconds. I'm not sure how the given equations help me relate the units at all.

I need current and power, but those units do not help me at all.

I know I = dq/dt, and I thought 45 C / 900 s looks very similar to current but the units don't make sense to me...
 
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Do you know how to determine how much heat it takes to raise the temperature of 1 kg of water from 15 C to 60 C?
 
Chestermiller said:
Do you know how to determine how much heat it takes to raise the temperature of 1 kg of water from 15 C to 60 C?

I'm not sure actually.. this chapter that I'm studying is called Current and Resistance..

It has to do with specific heat, right? Also, does heat = thermal energy?
 
Rijad Hadzic said:
I'm not sure actually.. this chapter that I'm studying is called Current and Resistance..

It has to do with specific heat, right? Also, does heat = thermal energy?
Yes. Did you not study heat in freshman physics?
 
Chestermiller said:
Yes. Did you not study heat in freshman physics?

I don't think I studied it enough..

So if the specific heat of water is 4.187 x 10^3 J/(kg * k )

That means it requires 4.187 x 10^3 J to raise 1 kg of water by 1 kelvin, correct?
 
Rijad Hadzic said:
I'm not sure actually.. this chapter that I'm studying is called Current and Resistance..

It has to do with specific heat, right? Also, does heat = thermal energy?
Yes, heat = thermal energy. To raise a kg water 1°C, you need 4184 Joules of heat (thermal energy).

http://www.kentchemistry.com/links/Energy/SpecificHeat.htm
 
What is the mass in kg of 40 gallons of water?
 
Last edited:
Chestermiller said:
What is the mass in kg of 40 gallons of water?

I think the asker had the converted number already [emoji846]. They wrote 151 kg.
 
Anyhow, using the heat you can now calculate the power (J/s). See that the heat is the 'J' and the time you have the 's'.

Now think about how you can get current!
 

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