Calculating Time, Where Did I Go Wrong?

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The discussion centers on calculating the time it takes for a doll to fall 50 meters into a river, using the equation of motion: x = x0 + v0t + 0.5at². The initial calculation yielded approximately 3.19 seconds, while the textbook answer is 2.3 seconds. The discrepancy arises from a misunderstanding of the acceleration term in the formula, specifically the factor of 0.5, which is derived from integration principles in physics.

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Homework Statement


A child accidentally drops her doll from a bridge suspended 50m above a fast moving river. Assuming the doll never reaches terminal velocity, how many seconds will it take for the doll to hit the water?

Homework Equations


x=x0+ v0t + 0.5*at2

The Attempt at a Solution


Using acceleration formula: x=x0+ v0t + 0.5*at2
It should be 0=(50M)+(0m/s)t+0.5*(-9.8m/s2)
Which would give me 3.194382825 seconds. The textbook's answer is 2.3s. So after a bit of exploration I realized that the acceleration isn't supposed to be halved. That brings me to the question why isn't the acceleration halved like the example and other questions using the formula?
 
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NafeesR said:

Homework Statement


A child accidentally drops her doll from a bridge suspended 50m above a fast moving river. Assuming the doll never reaches terminal velocity, how many seconds will it take for the doll to hit the water?

Homework Equations


x=x0+ v0t + 0.5*at2

The Attempt at a Solution


Using acceleration formula: x=x0+ v0t + 0.5*at2
It should be 0=(50M)+(0m/s)t+0.5*(-9.8m/s2)
Which would give me 3.194382825 seconds. The textbook's answer is 2.3s. So after a bit of exploration I realized that the acceleration isn't supposed to be halved. That brings me to the question why isn't the acceleration halved like the example and other questions using the formula?

Your answer is right (though you made a typo error and forgot a "t" in your equation.)
The factor 1/2 in front of the acceleration comes from integration.
 

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