Calculating Tire Pressure Change After a Drive

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SUMMARY

The discussion focuses on calculating the change in tire pressure after driving, specifically from an initial temperature of 16.0 C (289 K) and pressure of 20.0 psi to a final temperature of 38.0 C (311 K). The key formula used is the proportional relationship pf/pi = Tf/Ti, where pf is the final pressure and pi is the initial pressure. The pressure constant R is noted as 8.31, and the initial pressure is given as 1.36 atmospheres. The volume of the tire is assumed constant, and no additional air is added during the drive.

PREREQUISITES
  • Understanding of the Ideal Gas Law
  • Basic knowledge of temperature conversion (Celsius to Kelvin)
  • Familiarity with pressure units (psi and atmospheres)
  • Concept of proportional relationships in physics
NEXT STEPS
  • Study the Ideal Gas Law and its applications in real-world scenarios
  • Learn about tire pressure monitoring systems and their importance
  • Research the effects of temperature on gas pressure in closed systems
  • Explore methods for accurately measuring tire pressure
USEFUL FOR

Automotive engineers, physics students, and anyone interested in understanding the dynamics of tire pressure changes due to temperature variations.

mawalker
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On a cool morning, when the temperature is 16.0 C, you measure the pressure in your car tires to be 20.0 psi. After driving 50.0 mi on the freeway, the temperature of your tires is 38.0 C. What pressure will your tire gauge now show?

I have Ti = 289 K
Tf = 311 K
R = 8.31 pressure constant
pinitial = 1.36 atmosphere
n = ?
V = ?
I'm lost...
 
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mawalker said:
On a cool morning, when the temperature is 16.0 C, you measure the pressure in your car tires to be 20.0 psi. After driving 50.0 mi on the freeway, the temperature of your tires is 38.0 C. What pressure will your tire gauge now show?

I have Ti = 289 K
Tf = 311 K
R = 8.31 pressure constant
pinitial = 1.36 atmosphere
n = ?
V = ?
I'm lost...
You are not adding any air, so what happens to n? You can assume the volume does not change. You might need to think about what a tire gauge actually measures.
 
mawalker said:
On a cool morning, when the temperature is 16.0 C, you measure the pressure in your car tires to be 20.0 psi. After driving 50.0 mi on the freeway, the temperature of your tires is 38.0 C. What pressure will your tire gauge now show?

I have Ti = 289 K
Tf = 311 K
R = 8.31 pressure constant
pinitial = 1.36 atmosphere
n = ?
V = ?
I'm lost...
Use proportions: pf/pi=Tf/Ti.
 

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