Calculating Torque for Rack and Pinion Lifting System

  • Thread starter Thread starter SevenToFive
  • Start date Start date
  • Tags Tags
    Torque
Click For Summary

Discussion Overview

The discussion revolves around calculating the torque required to lift a 3600lb platen using a rack and pinion lifting system. Participants explore various mechanical design considerations, alternative lifting mechanisms, and the implications of using different systems for this application.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • One participant proposes a torque calculation formula, T=F*pitch/2*pi, suggesting approximately 22619in-lbs of torque is needed to lift the platen.
  • Another participant argues that treating the pinion as a lever indicates a need for 7200in-lbs just to maintain motion, considering the force's distance from the rotational center.
  • Questions are raised about the mechanical design background of the original poster and the choice of a rack and pinion mechanism, suggesting exploration of alternative mechanisms like linear screws or hydraulics.
  • Concerns are expressed regarding the suitability of spur gears and racks for this application due to lubrication issues and alignment challenges, recommending synchronous belts as a better alternative.
  • Another participant suggests using wire rope or continuous chain systems for lifting, highlighting cost-effectiveness and parts availability as advantages.
  • One participant emphasizes the importance of safety measures, such as guarding, in the design of the lifting system.

Areas of Agreement / Disagreement

Participants express differing views on the appropriateness of the rack and pinion system versus alternative mechanisms. There is no consensus on the best approach, as multiple competing views remain regarding the design and lifting methods.

Contextual Notes

Participants mention various assumptions and considerations, such as the need for acceleration and the implications of different lifting mechanisms, but these remain unresolved within the discussion.

Who May Find This Useful

Individuals interested in mechanical design, lifting systems, and torque calculations may find this discussion relevant, particularly those exploring different approaches to lifting heavy loads in engineering applications.

SevenToFive
Messages
56
Reaction score
3
I need some help calculating a rough approximation for the amount of torque needed to lift a 3600lb platen. We are planning on using a motor and worm gearbox to drive 4 pinions to lift the platen. I'm looking to move this platen 48 inches in 6 seconds. The pinion is 4" diameter.

Am I correct in T=F*pitch/2*pi, where T is torque(in-lbs), F is the force(3600lbs), Pitch diameter would be 4 inches,
T=3600lbs*4/2*pi giving me approximately 22619in-lbs of torque needed to lift the 3600lb load.
20181220_220008.jpg
 

Attachments

  • 20181220_220008.jpg
    20181220_220008.jpg
    15.5 KB · Views: 2,441
Engineering news on Phys.org
Not my field, but here goes just to get the thread started.
SevenToFive said:
Pitch diameter would be 4 inches,
T=3600lbs*4/2*pi giving me approximately 22619in-lbs of torque needed to lift the 3600lb load.
You need to treat the pinion as a lever. The 4in. pitch diameter places the force at 2in. from the rotational center. That shows you need 7200in-lbs just to keep it moving.

The other part of the problem is you need to accelerate that 3600lbs from a stand-still to a speed of around 8ft per second in 3sec. (Assuming it spends as much time getting up to speed as it does slowing to a stop.)

I'l let the mechanical experts take it from here.

Edit: The distance traveled per pinion revolution would be π⋅D, wher D is the pinion pitch diameter; about 12.57 inches with a 4in pitch dia.

Cheers,
Tom
 
Last edited:
SevenToFive said:
I need some help calculating a rough approximation for the amount of torque needed to lift a 3600lb platen. We are planning on using a motor and worm gearbox to drive 4 pinions to lift the platen. I'm looking to move this platen 48 inches in 6 seconds. The pinion is 4" diameter.
What is the platen used for -- what is this device?

What is your mechanical design background? Is there a reason you've chosen a Rack and Pinion mechanism to drive this platen? What is motivating the small size (4") of the Pinion gear? Have you considered other mechanisms to provide this lifting force? (linear screws, hydraulics, etc.)?
 
Spur gears and racks do not work well in this type of application. The gears need lubrication, which creates a mess. Alignment is critical. There are significant forces pushing the gear and rack apart. If you stay with gears and racks, you will need to calculate the strength of the gear teeth. The procedure is in any undergrad machine design textbook.

A better system is to support the platen with synchronous belts. Alignment is less critical, and there is no lubrication mess. A simple schematic of such a system is shown in Figure 1A of US Patent 6,641,358. The largest and fastest version of that separator has carriages that weigh 900 lbs, and make vertical moves at accelerations of 500 in/sec^2. The belts are Gates Poly Chain: https://www.gates.com/us/en/power-transmission/synchronous-belts/poly-chain-synchronous-belts/c/120

Another system that works well is screws at the four corners, with all of the screws driven by a single chain or synchronous belt. The screws can be large acme thread screws, or ball screws. The separator carriages shown in US Patent 7,364,398 were originally driven by, and supported by, ball screws. They operated very well and lasted a long time, but were messy because the paper dust environment required a lot of oil to the ball nuts, which leaked out and made a mess.

Don't forget guarding so that nobody can get, or even reach, underneath the platen. That is required by OSHA in the US, and the Machinery Directive in the EU. Guarding is both a legal and a safety requirement. Do not cut corners on guarding.
 
  • Like
Likes   Reactions: berkeman
Another lifting approach is use a wire rope (cable) or a continuous chain at each corner, with a pulley/sprocket at the top of the corner columns. The motive force is still applied at the bottom with either a drum to wind the wire rope or a sprocket to drive the chain.

The advantage of this approach is its cost effectiveness and greater parts availability.

For stability, I also recommend diagonally cross-bracing the corner posts. Or at least a frame around the top (and bottom if possible) with strong gussets.

Cheers,
Tom
 
Tom.G said:
Another lifting approach is use a wire rope (cable) or a continuous chain at each corner, with a pulley/sprocket at the top of the corner columns. The motive force is still applied at the bottom with either a drum to wind the wire rope or a sprocket to drive the chain.

The advantage of this approach is its cost effectiveness and greater parts availability.

For stability, I also recommend diagonally cross-bracing the corner posts. Or at least a frame around the top (and bottom if possible) with strong gussets.

Cheers,
Tom

I totally agree. A winch system (rope/pulley) would be much more flexible and cheaper. Gearing would come with strict requirement on tolerances. Rack and pinion are not exactly known for load bearing capacities compared to other systems.
 
  • Like
Likes   Reactions: berkeman

Similar threads

Replies
22
Views
3K
Replies
9
Views
2K
Replies
2
Views
7K
  • · Replies 17 ·
Replies
17
Views
5K
  • · Replies 18 ·
Replies
18
Views
3K
Replies
3
Views
3K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 3 ·
Replies
3
Views
4K