Calculating torque, force and angles

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SUMMARY

The discussion focuses on calculating the force P applied to a lever that lifts a box, with a moment of 500 N·m about point A. The lever length is 1.8 m, and the angle of application for force P is 15° at the end of the lever, while the lever itself makes a 43° angle at the pivot. Using the torque formula T = rFsinθ, the calculated force P is determined to be 1073 N, based on the provided parameters.

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  • Understanding of torque calculations using the formula T = rFsinθ
  • Knowledge of trigonometric functions, specifically sine
  • Familiarity with angles in physics, particularly interior angles between vectors
  • Basic principles of levers and moments in mechanics
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Homework Statement


A lever is used to lift a box, ignore the mass. the lever makes a 43° angle at the pivot, point A, the length of the lever is 1,8 m, Force P is apply 15° at the end of the lever
Force P causes a moment of 500N.m about point A. Determine the force P?

Homework Equations



T=rFsinθ

The Attempt at a Solution


T=rFsinθ
F=T/rsinθ
F=500/1.8sin15
F=1073N
 
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When using your formula for Torque, theta is the interior angle in between the force vector and the lever. Without a sketch, I don't know if you correctly determined theta. Welcome to PF!
 

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