Calculating Torque: Which Equation Should I Use?

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Calculating torque involves understanding two different equations: T = FD sin θ for mechanical forces and T = nBIA cos θ for current-carrying coils in magnetic fields. The confusion arises because the maximum torque for mechanical forces occurs at 90 degrees, while substituting 90 degrees in the second equation results in zero torque, as it indicates the coil is parallel to the magnetic field. The angle θ in the first equation refers to the angle between the force and displacement, while in the second equation, it is the angle between the coil's plane and the magnetic field. Clarifying these distinctions resolves the confusion regarding torque calculations in different contexts.
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Hello, i am confused in which equation to use when calulating torque...

my textbook equation for torque is T = FD sin theta

whilst the equation i have been taught is T = nBIA cos theta

and... my textbook says that torque will be the greatest when applied at right angles (90 degrees). However the cos theta eqn. if you sub cos 90 it equals 0. Hence no torque

what to do?

thanks
 
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First torque is due to a mechanical force. Here torque is maximum when the force is perpendicular to the displacement.
Second one the torque on a current carrying coil in a magnetic field. Here θ is the angle between the plane of the coil and the magnetic field.
 
rl.bhat said:
First torque is due to a mechanical force. Here torque is maximum when the force is perpendicular to the displacement.
Second one the torque on a current carrying coil in a magnetic field. Here θ is the angle between the plane of the coil and the magnetic field.

yea but for the second equation,when u sub θ =90 torque would equal zero, however when you sub zero you get a value. But θ = 0 means the coil is parallel with mag field hence no torque :S
 
Hello doc.madani! :smile:

(have a tau: τ and a theta: θ :wink:)

The θ in τ = nBIAcosθ is the angle between the direction of the field and the plane of the circuit.

The θ in τ = FDsinθ is the angle between the direction of the two forces (in the torque) and the displacement between the two forces.

The plane of the coil will contain a direction M perpendicular to the field, B. Let L be the direction perpendicular to M in the plane. We can assume that the coil is rectangular, with sides parallel to L and M.

The displacement between the M sides is parallel to L, and the direction of the force on those sides is also parallel to L, so the torque is zero.

The displacement between the L sides is parallel to M, and the direction of the force on those sides is perpendicular to B, in the plane of M and B, so the torque is proportional to the sin of the angle between M and the line "perpendicular to B, in the plane of B and M" …

in other words, the cos of the angle between M and B. :smile:
 


Thankyou Tiny-Tim very helpful :D
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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