Calculating Transformer Input Voltage

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SUMMARY

The forum discussion focuses on calculating the primary current and input voltage at a transformer using given parameters such as transformation ratio, resistances, and reactances. The transformation ratio is defined as a = N1/N2 = 0.1, with R1 = 0.12 Ω, R2 = 12 Ω, X1 = 0.4 Ω, and X2 = 40 Ω. The equivalent circuit calculations yield R1eq = 0.24 Ω and X1eq = j0.8 Ω, leading to a primary current Ip of 23 A. The discussion highlights the potential for a more efficient solution, particularly regarding the use of complex numbers in calculations.

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MechEngJordan
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Homework Statement



Calculate the primary current, and hence the voltage at the transformer input winding, V1.

Transformation ratio, a = N1/N2 = 0.1
R1 = 0.12 Ω; R2 = 12 Ω
X1 = 0.4 Ω ; X2 = 40 Ω
RC = 560 Ω
V2 = 2300 V
RL = 1 kΩ
'Xm = 800 Ω'

Homework Equations



R1eq = R1 + a2R2
X1eq = j(X1 + a2X2)
V2' = aV2

Current divider equation.

The Attempt at a Solution


[/B]
Approximate equivalent circuit:

Screenshot (206).png


R1eq = 0.12 + (0.1)2(12)
R1eq = 0.24 ΩX1eq = j(0.4 + (0.1)2(40))
X1eq =j0.8 Ω

V2' = 0.1(2300)
V2' = 230 V

a2ZL = (0.1)2(1000)
a2ZL = 10 Ω

Ip = V2'/a2ZL
Ip = 23 AFrom here is where I believed that there is likely a more efficient way to solve the problem -- particularly because the value of Xm was not actually given in the paper, but told to us during the tutorial, more-or-less made up on the spot.

Here is the outline of the given solution:

Ip= I1*Z2/(Z1+Z2)

⇒I1 = Ip*(Z1+Z2)/Z2

⇒I1 = 23*(Rc // Xm + X1eq + R1eq + a2ZL)/ (Rc // Xm)I0 = I1 - Ip

∴ V1 = I0(Rc // Xm)

I'd be thankful for any input.
 
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MechEngJordan said:
From here is where I believed that there is likely a more efficient way to solve the problem

It seems that in the given solution another equivalent is used (T-equivalent) than the one in #1. It's hard to explain what happens in that other equivalent because I cannot see what is meant by Z1 and Z2.

Don't you like to calculate with complex numbers? I don't know if you find complex calculations "more efficient", but they will be more structured. Example:

Z0 = (Rc || jXm) = (560 || j800) = (375.8 + j263). That's it.

In the same way you calculate other impedances, that can be used in Kirchhoffs laws, etc.

It becomes simple as in the given solution: Ip= I1*Z2/(Z1+Z2). As for the numerical calculation I assume a calculator can do the job for you.
 
Hesch said:
It seems that in the given solution another equivalent is used (T-equivalent) than the one in #1. It's hard to explain what happens in that other equivalent because I cannot see what is meant by Z1 and Z2.

Don't you like to calculate with complex numbers? I don't know if you find complex calculations "more efficient", but they will be more structured. Example:

Z0 = (Rc || jXm) = (560 || j800) = (375.8 + j263). That's it.

In the same way you calculate other impedances, that can be used in Kirchhoffs laws, etc.

It becomes simple as in the given solution: Ip= I1*Z2/(Z1+Z2). As for the numerical calculation I assume a calculator can do the job for you.

Hi,

Thanks for the reply.

I should have probably clarified that in this case,

Z1 = Rc // Xm

and

Z2 = X1eq + R1eq + a2ZL

I have no issues with complex numbers or the numerical computations; I suppose what I was referring to by 'efficient' was that in the original question, there was no value of Xm given (this was only given during the tutorial and seemed to be done off the cuff). This gave me the impression that the solution to this problem should have been different than the one given. Also, this was a 5-mark question and relative to other 5 mark questions, the given approach seemed like a lot of work.
 

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