Calculating Vehicle Distance: Kinematics Question on Brakes

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The discussion centers on calculating the distance a vehicle travels after applying brakes when approaching a traffic signal 400 meters away. The vehicle initially travels at 15 m/s and decelerates at 0.3 m/s². The correct calculation shows that after one minute, the vehicle would be 25 meters from the traffic light, confirming that the book's answer is accurate. The initial calculation of 40 meters was incorrect due to misunderstanding the braking duration.

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konichiwa2x
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Hi, can someone please check if this is right?

A driver applies brakes on seeing a traffic signal 400m ahead. At the time of applying the brakes, the vehicle was moving with 15m/s and retarding with 0.3m/s^2. What is the distance of the vehicle from the traffic light after 1 minute?

x = 15(60) - 1/2(0.3)(60)^2
x = 360m

Therefore the distance from the traffic light is 40m. Correct?
My book says the answer is 25m. Is it wrong? Any help will be appreciated.Thanks!
 
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I can't see anything wrong with your work. Either the book is wrong or we're both reading the question wrong (ie: the driver starts breaking after 1 second and then breaks for a minute)
 
konichiwa2x said:
Hi, can someone please check if this is right?

A driver applies brakes on seeing a traffic signal 400m ahead. At the time of applying the brakes, the vehicle was moving with 15m/s and retarding with 0.3m/s^2. What is the distance of the vehicle from the traffic light after 1 minute?

x = 15(60) - 1/2(0.3)(60)^2
x = 360m

Therefore the distance from the traffic light is 40m. Correct?
My book says the answer is 25m. Is it wrong? Any help will be appreciated.Thanks!

hey BOY,
SEE the driver has applied brakes so just calculate the time the car ll take to stop by the eq. v=u+at.Then just calc the dis by eq s=ut+1/2at^2...the dis ll be 375m.so dis from traffic light is 400-375 i.e 25 m dear.
PARAS sir
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