Calculating Velocity from Kinetic Energy: Solving for v in the r=mv/qb Formula

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SUMMARY

The discussion centers on calculating the velocity of a proton with a kinetic energy of 4.6×10-16 J moving in a magnetic field of 0.26 T, using the formula r=mv/qb. Participants clarify that the kinetic energy formula, KE = 1/2 mv2, can be rearranged to solve for velocity (v). To find v, one must first determine the mass of the proton, which is approximately 1.67×10-27 kg. This allows for the calculation of the radius of the proton's circular path in the magnetic field.

PREREQUISITES
  • Understanding of kinetic energy and its formula (KE = 1/2 mv2)
  • Knowledge of the relationship between force, mass, and acceleration (F = ma)
  • Familiarity with the concept of magnetic fields and their effects on charged particles
  • Basic algebra skills for rearranging equations
NEXT STEPS
  • Research the mass of a proton (1.67×10-27 kg) for accurate calculations
  • Learn how to manipulate the kinetic energy formula to solve for velocity
  • Explore the implications of magnetic fields on charged particles' motion
  • Study the relationship between radius, mass, charge, and magnetic field strength in circular motion
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Students in physics, educators teaching mechanics, and anyone interested in understanding the dynamics of charged particles in magnetic fields.

baylorbelle
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A proton with a kinetic energy of 4.6×10−16 J moves perpendicular to a magnetic field of 0.26 T. What is the radius of its circular path?


I know the formula is r=mv/qb. the only thing not given is v. So my question is how do I get v from Joules? I know 1 Joule=1N/m, and that N=ma, but I don't know how to get velocity from that. Any help on that part would be greatly appreciated : )
 
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What's the definition of kinetic energy?
 
1/2 mv^2
 
baylorbelle said:
1/2 mv^2
There you go. Now you can solve for v using the given information. (You may have to look up the mass of a proton.)
 
thanks!
 

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