Calculating Velocity from Vector Addition of Ion Positions

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Homework Help Overview

The problem involves calculating the average velocity of an ion based on its position vectors at two different times. The original poster presents initial and final position vectors and seeks to determine the average velocity over a specified time interval.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate average velocity using total displacement but initially adds the position vectors instead of subtracting them. Some participants clarify that displacement is the difference between final and initial position vectors.
  • Questions arise regarding the distinction between position vectors and displacement vectors, with the original poster comparing this problem to another scenario involving a train's motion.

Discussion Status

Participants have provided clarifications regarding the correct approach to finding displacement and have noted the difference between position and displacement vectors. The original poster acknowledges understanding after receiving feedback.

Contextual Notes

The original poster references a textbook answer that differs from their calculation, indicating potential confusion about vector addition versus subtraction in the context of displacement. There is also mention of a separate problem involving a train, which raises questions about vector types in different contexts.

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Homework Statement


An ion's position vector is initially r> = (5.0m)i - (6.0m)j = (2.0m)k and 10 s later it is r> = (-2.0m)i +(8.0m)j - (2.0m)k. In unit-vector notation, what is its during the 10 s?

The answer is supposed to be r> = (-0.7m/s)i + (1.4m/s)j - (0.4m/s)k (from back of my book) but I keep getting r> = (0.3m/s)i + (0.2m/s)j

Homework Equations


Vave> = r> (total) / T (total)

The Attempt at a Solution


r> = (5.0m)i - (6.0m)j = (2.0m)k
r> = (-2.0m)i +(8.0m)j - (2.0m)k.
+ -----------------------------
r> (total) = (3.0m)i + (2.0m)j

Vave> = r> (total) / T (total)
Vave> = (3.0m)i + (2.0m)j / 10sec
r> = (0.3m/s)i + (0.2m/s)j

I know my error doesn't have to do with the units, becasue I still end up with m/s in my answer. So where then did I go wrong?
 
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The displacement is the final position minus the initial position. You semed to have just added up the position vectors.
 
PhanthomJay said:
The displacement is the final position minus the initial position. You seemed to have just added up the position vectors.

Ah! That makes sense.

But I'm confused- my book says r>(total) = r1> + r>2 ...+ rn>

What makes this problem different than say this problem I will post at the bottom. In this other problem it was necessary to add the vectors instead of subtract. Is that becasue the problem you helped me with works with "position" vector and the problem at the bottom of the page works with some other type of vectors?

other problem:
"A train at a constant 60.0 km/h moves east for 40.0 min, then in a direction 50.0° east of due north for 20.0 min, and then west for 50.0 min. What are the (a) magnitude and (b) angle of its average velocity during this trip?"

Btw- I subtracted the vector and got the correct answer. Thank you.
 
Yes, the position vector specifies a point in reference to a coordinate system with its origin at (0,0,0), as in the first problem. The second problem uses displacement vectors.

Suppose you had a particle with an initial position vector of 2i + 2j, and a final position vector of 2i + 3j. Its displacement is obtained by subtracting the initial position vector from the final position vector, such that its displacement is just j (or 1 unit [N]). But if a a particle was displaced 2i +2j units and then 2i + 3j units, its displacement would be 4i + 5j. A quick sketch helps.
 
Thank you very much. I get it now.
 

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