Calculating Vibration Frequency of 1100 kg Car with 68 kg Driver

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Homework Help Overview

The discussion revolves around calculating the vibration frequency of a car with a specific mass and an additional driver's weight, focusing on the spring compression due to the driver's presence. The subject area includes concepts from mechanics, specifically related to oscillations and spring constants.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the spring constant using the driver's weight and the compression distance. There are attempts to clarify the correct units and the need to consider the total mass resting on the springs for accurate period calculations.

Discussion Status

The discussion is active, with participants providing guidance on unit conversions and the importance of using the combined mass of the car and driver. There are differing opinions on the correct approach to calculating the period of oscillation, indicating ongoing exploration of the problem.

Contextual Notes

Participants note the importance of using SI units and the potential confusion regarding the application of forces and masses in the calculations. There is acknowledgment of approximations in the expected period of oscillation.

LostTexan07
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The springs of a 1100 kg car compress 6.0 mm when its 68 kg driver gets into the driver's seat. If the car goes over a bump, what will be the frequency of vibrations?

I tried to use the weight of the man (68 kg) and the compression distance (6 mm) to find the spring constant. I then tried to use the spring constant to find the period.

F = kx
68 = 6k
k = 11.33

T = 2(pi)(sq.rt 1100/11.33)

But I didn't get the correct answer.
 
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When you calculate k, first convert mm to m. 6.0mm = 6.0*10^-3m

When you calculate T, use the mass of the man = 68kg. not the mass of the car.
 
Also, the driver's mass is 68 kg., but you need the added weight of the driver applied to the springs. The spring constant, k, needs to be expressed in SI units, which are Newtons/m, which is why learningphysics corrected your 6 mm entry.

For the period of oscillation, you will need the combined mass of car and driver. (I'll say that the answer is in the neighborhood of 0.6 second.)
 
Last edited:
Yes, sorry you need to use:

F = kx

mg = kx (with m = 68kg) to find k...

I didn't notice the g was missing.

dynamicsolo, I'm not getting 0.6 for the period like that... are you sure about using the combined mass of the car and the person?
 
learningphysics said:
dynamicsolo, I'm not getting 0.6 for the period like that... are you sure about using the combined mass of the car and the person?

You do use the total mass (1168 kg.) now resting on the springs for this "oscillator". The figure I gave for the period is approximate because I didn't want to just provide the answer. [k should be around 111,000 N/m and sqrt(m/k) is roughly 0.1 sec.]
 
dynamicsolo said:
You do use the total mass (1168 kg.) now resting on the springs for this "oscillator". The figure I gave for the period is approximate because I didn't want to just provide the answer. [k should be around 111,000 N/m and sqrt(m/k) is roughly 0.1 sec.]

Oh, I see my problem. I was thinking the springs described were "in" the driver's seat... sorry about that.

yes, I get around 0.6. I must have been plugging in something wrong.
 

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