Calculating Vo for a Basketball Shot at 40 Deg Angle

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SUMMARY

The discussion focuses on calculating the initial velocity (Vo) required for a basketball player to successfully shoot a ball through a hoop from a distance of 10 meters at a 40-degree angle. The player is 2.00 meters tall, and the hoop is positioned at 3.05 meters. The equations used include time of flight (t = 10/(Vo * COS(40))) and vertical motion (1.05 = (Vo * SIN(40)) * t - 4.9 * t^2). By substituting the expression for t into the vertical motion equation, one can isolate Vo to find the necessary initial speed.

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A 2.00m tall basket ball player is standing on the floor 10m from the basket. If he shoots the ball at 40 degrees angle with the horizontal, at what initial speed must he throw the basketball so that i goes through the hoop? The height of the basket is 3.05m.

Here how do i calculate for Vo?
i get t=10/(VoCOS40) and 1.05=(VoSIN40)t - 4.9t^2
 
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Substitute that t into your y distance equation and do some manipulation so that V0 is the subject.
 

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