Calculating Voltage Drop Across 5kOhm Resistor

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Homework Help Overview

The problem involves a 6V DC voltage source connected in series with a 5kΩ resistor and a 10 nF capacitor, focusing on determining the voltage drop across the resistor.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the equation Q=CV, but question its relevance to finding the voltage drop across the resistor. There is mention of Kirchhoff's law and its applicability, with some participants indicating a lack of familiarity with it.

Discussion Status

The discussion is ongoing, with participants exploring different perspectives on how to approach the problem. Some guidance has been offered regarding the operation of capacitors and the implications of charging, but there is no explicit consensus on the method to solve the problem.

Contextual Notes

One participant notes that there may not be enough information provided to fully address the question.

myoplex11
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Homework Statement


A 6V DC voltage source is connected across both a 5kohm resistor and a 10 nF capacitor in series. The voltage drop across the resistor is what?
Reply With Quote


Homework Equations



Q=CV

The Attempt at a Solution


Q= (10*10^-9 F)(5000ohms)
 
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myoplex11 said:

Homework Statement


A 6V DC voltage source is connected across both a 5kohm resistor and a 10 nF capacitor in series. The voltage drop across the resistor is what?
Reply With Quote


Homework Equations



Q=CV

The Attempt at a Solution


Q= (10*10^-9 F)(5000ohms)

Q = CV does not have anything to do with finding the voltage drop across the resistor. Q here refers to the charge, C is the capacitance and V is the voltage.

Did you learn about Kirchoff's law? Use Kirchoff's voltage law to solve this.
 
no we did not learn kirckoffs law
 
Did you learn how a capacitor works? KVL is really not needed.

Think what happens when the capacitor is not charged at all and what happens when it is fully charged.

There is not enough information given here in my opinion.
 

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