Calculating Volume Change for an Air Bubble Rising from Depth

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The discussion focuses on calculating the volume change of an air bubble as it rises from a depth of 125 meters in freshwater. The initial volume of the bubble is 1.75 cm³, and the pressure at that depth is calculated to be 1,326,325 Pa. Using the formula P1*V1=P2*V2, where P2 is the atmospheric pressure of 101,325 Pa, the final volume of the bubble when it reaches the surface is determined to be 22.90 cm³. The calculations confirm that the pressure above the water is indeed 101,325 Pa.

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An air bubble has a volume of 1.75 cm3 when it is released by a submarine 125 m below the surface of a lake. What is the volume of the bubble when it reaches the surface? Assume that the temperature of the air in the bubble remains constant during ascent.

P= a+h*g*density

a=101325Pa
h=125m
g=9.8
density of freshwater=1000kg/m^3

P1*V1=P2*V2
1326325Pa*1.75cm3=101325*V2

V2=22.90cm3?

when calculate the initial pressure i get 1326325Pa so that would be the pressure under the water and the pressure above the water would just be 101325Pa?

Am i doing this right?
 
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