# Determine bubble volume change with given temperature

1. Jul 13, 2014

### hummele

1. The problem statement, all variables and given/known data

A 1-cm3 air bubble at a depth of 141 meters and at a temperature of 4 degrees Celsius rises to the surface of the lake where the temperature is 13.1 degrees Celsius, to the nearest tenth of a cm3, what is its new volume?

2. Relevant equations

P1V1/T1=P2V2/T2

3. The attempt at a solution

I have trying to use previous posts to help me, but I do not know where I am going wrong. I attempted using these numbers.

((1.013x105)+(1000x9.8x141)(1)(286.25))/(1.013x102)(277.15)

However, I don't know if I am supposed to use (1.013x105) or 1000 because they are not given in the original problem.

Last edited: Jul 13, 2014
2. Jul 13, 2014

### Staff: Mentor

Please work with units, that makes things much easier. It looks like the brackets are wrong - something easy to spot if you work with units as they won't match there.

I guess the 102 in the denominator is a typo?

I think it does not matter which surface pressure you use, as long as you make it clear what you use. The effect is small and I guess for the rounded result both choices give the same value.

3. Jul 16, 2014

### Maharshi Roy

The P2 value is incorrect.