SUMMARY
The discussion centers on calculating the water output of a 2.0 hp electric motor pumping water from a depth of 10 meters. The motor operates at 1491.6 Watts (2 hp x 745.8 Watts) and utilizes the potential energy formula PE = mgh to determine the mass of water pumped in one hour. The gravitational acceleration is clarified as 9.79 m/s², leading to the conclusion that the volume of water pumped can be directly related to its mass, with 1000 liters equating to 1000 kg. The participants emphasize the importance of understanding energy calculations in this context.
PREREQUISITES
- Understanding of basic physics concepts, specifically potential energy (PE = mgh)
- Familiarity with power conversion (1 hp = 745.8 Watts)
- Knowledge of gravitational acceleration values (g = 9.79 m/s²)
- Basic understanding of volume and mass relationships in water (1 liter = 1 kg)
NEXT STEPS
- Research the implications of power output on pump efficiency
- Learn about the relationship between horsepower and water flow rates
- Explore the effects of varying depths on pump performance
- Investigate the calculations for energy consumption in electric motors
USEFUL FOR
This discussion is beneficial for mechanical engineers, physics students, and anyone involved in designing or analyzing water pumping systems using electric motors.