Calculating Water's Landing Point From a Hole in a Pool

[physhelp90]

Homework Statement

A swimming pool is filled with water. It is 2.50 m tall and 3.00 m in diameter. There is a small 1.00 cm (in diameter) hole in the side of the pool and its 0.50 m below the top. How far from the pool will the water coming out of the hole land?

Homework Equations

The Attempt at a Solution

Here's my attempt using Torricelli's theorem, however I need to use Bernoulli's equation any help is appreciated.

Vx = Sqrt 2g(2.50 - 1.00)
Vx = 5.42 m/s This is the horizontal velocity.

t= sqrt 2h/g = .20 seconds = time water is in air

x = t x Vx

x = 1.11 meters ?

 

[aerospaceut10]

Well, do you know what Bernoulli's equation is?

If you know that, then so you basically just need to find the pressure at the level where the hole is, then set that equal to dynamic pressure and solve for the velocity value, which should all be in the x direction.

 

[naresh]

I'm really having trouble imagining a swimming pool (2.5 m tall) with a hole and water leaking out of the side of this swimming pool and landing somewhere. It's like watching a movie - you need to suspend your disbelief

Sorry, don't mind me - please go ahead and solve the problem.

 

[wisemo]

Hello
just check the attached doc for the answer method.

tc
mo

 

[aerospaceut10]

I'm really having trouble imagining a swimming pool (2.5 m tall) with a hole and water leaking out of the side of this swimming pool and landing somewhere. It's like watching a movie - you need to suspend your disbelief

Sorry, don't mind me - please go ahead and solve the problem.

The pool is standing above ground. Maybe imagine it as just a giant water tank/cylinder?