Calculating Wave Speeds of Steel Guitar Strings

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Ignis Radiis
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Homework Statement


Two steel guitar strings have the same length. String A has a diameter of 0.50 mm and is under 410.0 N of tension. String B has a diameter of 1.0 mm and is under a tension of 820.0 N. Find the ration of the wave speeds, VA / VB
in these two strings.

Homework Equations


V= ƒ λ
FT = FG

The Attempt at a Solution


I'm lost on where to start...:oldcry::oldconfused::oldconfused::oldcry:
 
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Ignis Radiis said:

Homework Statement


Two steel guitar strings have the same length. String A has a diameter of 0.50 mm and is under 410.0 N of tension. String B has a diameter of 1.0 mm and is under a tension of 820.0 N. Find the ration of the wave speeds, VA / VB
in these two strings.

Homework Equations


V= ƒ λ
FT = FG

The Attempt at a Solution


I'm lost on where to start...:oldcry::oldconfused::oldconfused::oldcry:
Amongst your standard equations, you should have one that relates wave speed in a string/wire to tension and mass per unit length.
 
Ignis Radiis said:

Homework Statement


Two steel guitar strings have the same length. String A has a diameter of 0.50 mm and is under 410.0 N of tension. String B has a diameter of 1.0 mm and is under a tension of 820.0 N. Find the ration of the wave speeds, VA / VB
in these two strings.

Homework Equations


V= ƒ λ
FT = FG

The Attempt at a Solution


I'm lost on where to start...:oldcry::oldconfused::oldconfused::oldcry:
v=√(T/¢)
T= tension in wire
¢= mass per unit length