Calculating Work Done by a Beaver in Building a Dam

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Homework Help Overview

The problem involves calculating the work done by a beaver while climbing a ladder with a bucket of water that leaks. The scenario includes a beaver starting with a bucket containing a specific mass of water and experiencing a change in mass due to leakage as it ascends a vertical height.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to express the mass of the bucket and water as a function of height and time. There are attempts to derive equations for mass based on height and to integrate these expressions to find work done.

Discussion Status

The discussion is ongoing, with participants exploring different methods to express mass and questioning the correctness of their approaches. Some guidance has been offered regarding the need to integrate force with respect to height rather than mass.

Contextual Notes

There is uncertainty regarding the time taken to climb and the specific height of the ladder, which affects the calculations. The original poster's initial assumptions and expressions are being scrutinized and refined by other participants.

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Homework Statement


A beaver is building a damn and fills a 5kg bucket with 25kg of water. Then he begins to climb a vertical ladder, but unfortunately there is a whole in the bucket where water leaks out at a constant rate. At the top of the ladder, only 10kg of water is left in the bucket. Find the work done by the beaver in this problem.

Hint: Speed up the ladder is constant and writing an expression for mass of the bucket plus water as a function of height will help.


Homework Equations


(I believe):
PE=mgh
KE=(1/2)mv^2
Integrals


The Attempt at a Solution



Well, I want to start with writing the expression and then integrating that, but I don't know what the expression should be... h=Mb+Mw seems too easy, or is this what they meant at first and then to do something with the PE equation and height?? Ack!
 
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First you need an expression for the mass of water as function of time.
The mass is decreasing at a constant rate. Initially, it is 25kg. The final mass is 10 kg. The total time needed to climb up is T. t is the running time. Draw a plot first, and then write the expression for m(t).

ehild
 
Well, we don't know the time and the hint says to write mass as a function of height, so I went ahead and used the old school skills to get mass as a function of height:
m(h)=-1.25h+30

...sooo, now should I be using integrals? Or am I taking the wrong approach?
 
Okay, so integrating I get:
12(30-0.655(12)) - 0 = 270 J

Is this correct?
 
I do not understand your old school skills. What is h at the top of the ladder? Will be the mass of water equal to 10 kg there?
 
h at the top (at 12m) is 15 (10kg water plus 5kg bucket)
h at the bottom (at 0m) is 30 (25kg water plus 5kg bucket)

So I used these as coordinates (0,30) and (12,15) and have the equation
m(h)=-1.25h+30
 
So the heigh was given? You did not write it in the first post. Then the mass is all right. But you should integral the force with respect to h. As I see, you have integrated the mass. And I do not know either, where that 0.655 comes from.

ehild
 

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