Calculating Work Done by a Constant Force on a Moving Body

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SUMMARY

The discussion centers on calculating the work done by a constant force on a moving body, specifically a force F with components Fx=3N and Fy=4N acting on a body moving from point P (2 m, 6 m) to point Q (14 m, 1 m). The correct calculation of work is achieved using the dot product formula, resulting in W = F • s = 16 J. Participants confirmed this result through detailed calculations involving vector components and displacement.

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swarm17
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Homework Statement


I have this packet and one of the questions state:
The constant force F with components Fx=3N and Fy=4N act on a body while that body moves from the point P (x=2 m, y=6 m) to the point Q (x=14 m, y=1 m). How much does the force do on the body during this process?

the options are as follows:
a. 16 J
b. 30 J
c. 46 J
d. 56 J
e. 65 J

Homework Equations



I have the equations to find energy:
kinetic: K=(1/2)mv^2
gravitational: mgh

The Attempt at a Solution



but I'm not sure if I'm missing something. So far I have figured out you need to keep the x and y components separated and calculate each but I think I'm doing something wrong. I've gotten to Work = Force * cos(t) * change in distance but I'm just confusing myself. Help?

Also, I am taking the Physics: C Mechanics exam, what are some topics and questions that would help me prepare for it?
 
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Do you know what a dot product is?
 
I don't know what a dot product is other than its used in calculus
 
swarm17 said:
I don't know what a dot product is other than its used in calculus

It is quite a simple operation, I am sure you must have come across it in high school maths, but for a refresher...

Dot product is defined as:
<br /> a_{i} b_{j}\delta_{ij}=a_{i} b_{i}

Example:
<br /> \vec{a} = (2\hat{e}_{1} +2\hat{e}_{2} + 2\hat{e}_{3} )<br />
<br /> \vec{b} = (0\hat{e}_{1} +2\hat{e}_{2} + 4\hat{e}_{3} )<br />

then
<br /> a_{i} b_{j}\delta_{ij}= ( 2 \bullet 0) + (2 \bullet 2) + (2 \bullet 4)<br />
<br /> a_{i} b_{j}\delta_{ij}= 12<br /> <br />
 
You have the right formula. But it easier to use the dot product formula (which may be used by people that don't know calculus)

W = Fxdx+Fydy+Fzdz.

Those are the components of the forceF and the displacement d.

EDIT: TheAustrian beat me to the punch
 
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Would the answer be a. 16 J?
I used:
F=(3i+4j) N
s=(14-2i + 1-6j)
m = 12i+-5j) m
W=f•s=36-20=16J
16 J?
 
Yeah, that looks right.
 
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swarm17 said:

Homework Statement


I have this packet and one of the questions state:
The constant force F with components Fx=3N and Fy=4N act on a body while that body moves from the point P (x=2 m, y=6 m) to the point Q (x=14 m, y=1 m). How much does the force do on the body during this process?

the options are as follows:
a. 16 J
b. 30 J
c. 46 J
d. 56 J
e. 65 J

Homework Equations



I have the equations to find energy:
kinetic: K=(1/2)mv^2
gravitational: mgh

The Attempt at a Solution



but I'm not sure if I'm missing something. So far I have figured out you need to keep the x and y components separated and calculate each but I think I'm doing something wrong. I've gotten to Work = Force * cos(t) * change in distance but I'm just confusing myself. Help?

Also, I am taking the Physics: C Mechanics exam, what are some topics and questions that would help me prepare for it?
Is this problem from a practice test or is it from a current AP test ?
 
SammyS said:
Is this problem from a practice test or is it from a current AP test ?
It is from a set of free sample test questions posted on the College Board website.

swarm17, hope everything went well for you yesterday!
 

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