Calculating Work Done by Car Engine

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Nanu Nana
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Homework Statement


A car (mass 900 kg) runs 12 km along a level road at a constant speed of 80 km / h. The friction force is 500N. Calculate the work done by the engine

Homework Equations


W= F x displacement[/B]

The Attempt at a Solution


W= (900x 9.81) N x 12000m
W=10594800 J
But this is wrong .answer should be 6 x10^6 J
 
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Nanu Nana said:

Homework Statement


A car (mass 900 kg) runs 12 km along a level road at a constant speed of 80 km / h. The friction force is 500N. Calculate the work done by the engine

Homework Equations


W= F x displacement[/B]

The Attempt at a Solution


W= (900x 9.81) N x 12000m
W=10594800 J
But this is wrong .answer should be 6 x10^6 J
(900 kg)(9.81 m/s2) is the forge due to gravity. It acts in a direction perpendicular to the displacement of the car, so that force does zero work.

What force must the engine overcome to maintain the car's sped?
 
oh friction force
so
Work = Friction force x (12000m)
W= 500 N x 12000m
W=6 x10^6 Joule
 
SammyS said:
Correct !
Thank you very much . Where on forum should i ask if i want explanation about vectors components?
 
Nanu Nana said:
Thank you very much . Where on forum should i ask if i want explanation about vectors components?

Nanu Nana said:
Thank you very much . Where on forum should i ask if i want explanation about vectors components?

First, look in your textbook. If you cannot find a satisfactory answer there, go next to the internet; Google "vectors" or "vector components" or "vectors in physics", or similar entries. If you still have not found a satisfactory answer, THEN come to this Forum and ask a specific question (not a general question like 'can someone tell me about vector components?')
 
Nanu Nana said:
Thank you very much . Where on forum should i ask if i want explanation about vectors components?
If it's a from a homework problem or closely related to one, then this is the correct forum.

If it's more general, then either this forum or the General Physics section of the Physics section.
 
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Nanu Nana said:
A car (mass 900 kg) runs 12 km along a level road at a constant speed of 80 km / h. The friction force is 500N. Calculate the work done by the engine
Calling the resistance to a car's normal motion simply 'friction' is one of my pet hates. It's so confusing for students. What the question means is some combination internal friction (bearings etc.), rolling resistance and drag. The friction between the tyres and the road is precisely what allows the car to get anywhere. In the context of the problem, it would be acting in the forward direction.
 
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I agree, calling it friction is misleading but just for completeness... If we ignore internal/bearing friction then the forward pointing friction between tyre and road is equal to the rearward forces such as rolling resistance and drag.