Problem in calculating work done?

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Homework Help Overview

The discussion revolves around a problem related to calculating work done, specifically using the integral form of work, which involves force and displacement. The original poster attempts to apply integration to solve the problem but encounters difficulties in substituting variables correctly.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the correct substitution in the integral for work done, questioning the validity of replacing displacement with a function of time. Some participants provide insights into the relationship between displacement and its derivative, raising questions about the original poster's approach.

Discussion Status

The discussion is ongoing, with participants providing clarifications about the substitution process and the relationship between variables. There is an emphasis on understanding the correct interpretation of the terms involved in the integral.

Contextual Notes

Participants note that the original poster has not been given a direct expression for ds or dx, which is central to the discussion about the substitution made in the integral.

navneet9431
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Homework Statement


IMG_20180817_085052.jpg

See question number 3

Homework Equations


Work Done="integral" F*ds

The Attempt at a Solution


I tried to solve this question using integration,
IMG_20180817_085548.jpg

I have replaced F with "1" and ds with "t^2+2t".
So I am stuck in at that step.
Please help me differentiate it further or solve it further!
I will be thankful for any help!
 

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In the integral it’s ##F*ds## which becomes ##F*dx## so you can’t just sub in the ##t^2+2t## term.

##dx/dt = 2t+2## and so ##dx = (2t+2)dt##
 
jedishrfu said:
In the integral it’s ##F*ds## which becomes ##F*dx## so you can’t just sub in the ##t^2+2t## term.

##dx/dt = 2t+2## and so ##dx = (2t+2)dt##
Thanks for the reply!
But can you please explain why is it wrong to substitute "t^2+2t" in place of ds?
 
navneet9431 said:
Thanks for the reply!
But can you please explain why is it wrong to substitute "t^2+2t" in place of ds?
You are not given ds (or dx)= t2+2t; you are given x=t2+2t. So what does dx equal?
 
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