The discussion focuses on calculating the work done by friction on a 55 kg cart subjected to a 200 Newton horizontal force over a 10-meter distance. The cart accelerates at 2 meters/second squared, leading to a calculation of work done by friction as 900 Joules. The correct approach involves using a free body diagram to identify all acting forces, including friction, and applying the work formula: Work = Force x Distance. This method ensures accurate determination of the work done against friction.
PREREQUISITESStudents studying physics, educators teaching mechanics, and anyone interested in understanding the dynamics of forces and motion in practical scenarios.
Oddly enough your answer is correct. But I have no idea what you are doing.williamx11373 said:a horizontal force of 200 Newtons is applied to a 55 kg cart across a 10 meter surface. If the cart accelerates at 2 meters/second squared, then what is the work done by the force of friction as it acts to retard the motion of the cart ??
Work= FX
work= maX
55 kg x 2 x 10 = 1100 - 200 N = 900 Joules ??