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When you compress a spring and release it (allowing object to spring some distance), to compute the work done by friction, your s term in W=Fs would have to equal the distance that the spring is compressed + the additional distance traveled by the object once it leaves the spring, right?

That's what I alwasy thought, but in one of my problems, it uses an s value that equals ONLY the distance traveled by the object after it surpasses the point of the uncompressed spring.

Ryan

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# Homework Help: Calculating work done by friction

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