Calculating Work Done by Friction

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SUMMARY

The discussion centers on calculating the work done by friction when pushing a refrigerator with a force of 297 N over a distance of 2.8 m at a constant velocity. The correct formula for work is W = F × d, where F is the force and d is the distance. The initial attempt incorrectly used power equations, leading to an erroneous calculation of 124 J. The accurate work done by friction is determined by the applied force and the distance moved.

PREREQUISITES
  • Understanding of basic physics concepts, specifically work and friction.
  • Familiarity with the formula W = F × d for calculating work.
  • Knowledge of constant velocity and its implications on net force.
  • Ability to differentiate between work and power equations.
NEXT STEPS
  • Study the relationship between force, distance, and work in physics.
  • Learn about the concept of friction and its role in work calculations.
  • Explore the differences between work and power, including their respective formulas.
  • Review practical examples of calculating work done in various physical scenarios.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone seeking to understand the principles of work and friction in mechanical systems.

rfig08d
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Homework Statement



You are pushing a refrigerator across the floor of your kitchen. You exert a horizontal force of 297 N for 6.7 s, during which time the refrigerator moves a distance of 2.8 m at a constant velocity.

What is the work done by friction?

Homework Equations



W=fv
w=f(d/t)

The Attempt at a Solution



w=297(2.8/6.7) = 124 J.

Why is this answer incorrect?
Any info to the right direction is much help :) thanks
 
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Edit - Right, it'll be -FΔx.

Thanks.
 
Last edited:

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